Can someone please answer this question please answer it correctly and please show work

answer:

#32:  C - 3/5

#33:  C - 1/2

#47:  h ≤ 5 -> Inequality, This solution set shows that she can get 5 or less pounds of ham.  Otherwise if she gets more, she will exceed the $35 budget.  

Step-by-step explanation:

#32

Step 1:  Make an equation to fit the situation

So, there are a total of 15 Dvd's and 6 of them are comedy and the rest of them are drama.  So if the rest are drama, that means 6 + x = 15.

6 + x - 6 = 15 - 6

x = 9

Step 2:  Find the Probability

To find the probability, you need to divide the occurrence over the total.

For this problem the occurrence is drama which is 9 and the total is 15 dvds.

9/15 which simplifies to 3/5

Answer for #32 is C

#33

Step 1:  Look at the end of the chart to see how much heads and how much tails.

4 heads, 4 tails

Step 2:  Find the Probability

To find the probability, you need to divide the occurrence over the total.

The occurrence in this problem is H which is 4 and the total is 8.

4/8 which simplifies to 1/2

Answer for #33 is C

#47

Step 1:  Make an equation to represent the situation

So, there are $35 to spend, and she already spent $5 for bread.  She also wants to buy ham which costs $6 per pound.

6h + 5 ≤ 35

Step 2:  Solve for h to get the inequality

6h + 5 - 5 ≤ 35 - 5

6h / 6 ≤ 30 / 6

h ≤ 5 -> Inequality

Step 3:  Explain  

This solution set shows that she can get 5 or less pounds of ham.  Otherwise if she gets more, she will exceed the $35 budget.  

3,000,540

step-by-step explanation:

(2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))

step-by-step explanation:

simplify the following:

x/x^2 + 3 x + 2 - (x (x + 1))/(x + 2)

combine powers. x/x^2 = x^(1 - 2):

x^(1 - 2) + 3 x + 2 - (x (x + 1))/(x + 2)

1 - 2 = -1:

x^(-1) + 3 x + 2 - (x (x + 1))/(x + 2)

put each term in 1/x + 3 x + 2 - (x (x + 1))/(x + 2) over the common denominator x (x + 2): 1/x + 3 x + 2 - (x (x + 1))/(x + 2) = (x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)):

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2))

(x + 2)/(x (x + 2)) + (3 x^2 (x + 2))/(x (x + 2)) + (2 x (x + 2))/(x (x + 2)) - (x^2 (x + 1))/(x (x + 2)) = ((x + 2) + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2)):

(2 + x + 3 x^2 (x + 2) + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

3 x^2 (x + 2) = 3 x^3 + 6 x^2:

(2 + x + 3 x^3 + 6 x^2 + 2 x (x + 2) - x^2 (x + 1))/(x (x + 2))

2 x (x + 2) = 2 x^2 + 4 x:

(2 + x + 6 x^2 + 3 x^3 + 2 x^2 + 4 x - x^2 (x + 1))/(x (x + 2))

-x^2 (x + 1) = -x^2 - x^3:

(-x^2 - x^3 + 3 x^3 + 6 x^2 + 2 x^2 + 4 x + x + 2)/(x (x + 2))

grouping like terms, 3 x^3 - x^3 + 6 x^2 + 2 x^2 - x^2 + 4 x + x + 2 = (3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2:

((3 x^3 - x^3) + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

3 x^3 - x^3 = 2 x^3:

(2 x^3 + (6 x^2 + 2 x^2 - x^2) + (x + 4 x) + 2)/(x (x + 2))

6 x^2 + 2 x^2 - x^2 = 7 x^2:

(2 x^3 + 7 x^2 + (x + 4 x) + 2)/(x (x + 2))

x + 4 x = 5 x:

answer:   (2 x^3 + 7 x^2 + 5 x + 2)/(x (x + 2))