A consumer electronics firm has developed a new type of remote control button that is designed to operate longer before becoming intermittent. A random sample of 35 of the new buttons is selected and each is tested in continuous operation until becoming intermittent. The resulting lifetimes are found to have a sample mean of = 1,241.2 hours and a sample standard deviation of s = 110.8. Assuming normality of the population, the p-value for testing H0 versus Ha can be calculated to be .0174. (a) Determine whether H0 would be rejected at each of α = .10, α = .05, α = .01, and α = .001.

At 0.10 significance level, reject H0

At 0.05 significance level, reject H0

At 0.01 significance level, fail to reject H0

At 0.001 significance level, fail to reject H0

Step-by-step explanation:

The null hypothesis is rejected if the p-value is less than or equal to the significance level.

Fail to reject the null hypothesis if the p-value is greater than the significance level.

At 0.1 and 0.05 significance level, the null hypothesis is rejected because the p-value (0.0174) is less than the significance levels.

At 0.01 and 0.001 significance level, fail to reject the null hypothesis because the p-value (0.0174) is greater than the significance levels.

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

be more specific

step-by-step explanation: