A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second. the nuts height, h, at time t seconds can be represented by the equation h(t)=-16t^2+8t+24. if the squirrel climbs down the tree in 2 seconds, does it reach the ground before the nut?

The nut lands first on gorund

Solution:

The squirrel climbs down the tree in 2 seconds

Given that,

A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second

The nuts height, h, at time t seconds can be represented by the equation:

time cannot be negative, so ignore t = -1

Thus the nut takes 1.5 seconds to reach ground

From given,

The squirrel climbs down the tree in 2 seconds

Therefore, the nut lands first on gorund

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )