Jesse sold cupcakes and cookies yesterday. Each cupcake sold for $1.50 and each cookie sold for $0.25. At the end of the day, Jesse had sold $37.75 worth of cookies and cupcakes. If he sold 56 cupcakes and cookies combined, how many cupcakes were sold and how many cookies were sold?

19 cupcakes and 37 cookies were sold.

Step-by-step explanation:

Let x represent the number of cupcakes that Jesse sold yesterday.

Let y represent the number of cookies that Jesse sold yesterday.

If he sold 56 cupcakes and cookies combined, it means that

x + y = 56

Each cupcake sold for $1.50 and each cookie sold for $0.25. At the end of the day, Jesse had sold $37.75 worth of cookies and cupcakes. This means that

1.5x + 0.25y = 37.75 - - - - - - - - - - -1

Substituting x = 56 - y into equation 1, it becomes

1.5(56 - y) + 0.25y = 37.75

84 - 1.5y + 0.25y = 37.75

- 1.5y + 0.25y = 37.75 - 84

- 1.25y = - 46.25

y = - 46.25/ - 1.25

y = 37

x = 56 - y = 56 - 37

x = 19

a 10 percent increase

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)