Find f(1) if.
f(x)=x^3+2x^2-x-1

1

Step-by-step explanation:

f(x)=x^3+2x^2-x-1

f(1)=1^3+2(1)^2-1-1

f(1)=1+2*1-1-1

f(1)=1+2-1-1=3-1-1=2-1=1

i pretty sure it is

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function