Faculty members at Lowell Place High School want to determine whether there are enough students to have a Valentine's Day Formal. Eighty-eight of the 200 students said they would attend the Valentine's Day Formal. Construct and interpret a 90% confidence interval for p.

The 90% confidence interval is (0.4977, 0.5023). We are 90% confident that the true proportion of students attending the Valentine's Day Formal is between 49.77% and 50.23%.
The 90% confidence interval is (0.3823, 0.4977). There is a 90% chance that a randomly selected student who will attend the Valentine's Day Formal lies between 38.23% and 49.77%.
The 90% confidence interval is (0.4977, 0.5023). Ninety percent of all samples of this size will yield a confidence interval of (0.4977, 0.5023).
The 90% confidence interval is (0.3823, 0.4977). Ninety percent of all samples of this size will yield a confidence interval of (0.3823, 0.4977).
The 90% confidence interval is (0.3823, 0.4977). We are 90% confident that the true proportion of students attending the Valentine's Day Formal is between 38.23% and 49.77%.

The answer & explanation for this question is given in the attachment below.

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!