The equation of a straight line is 2y = 3x + 4.

a. Find the graduent of this line.

b. Find the co-ordinates of the point where the line crosses the y-axis.

Please answer fast

The standard form for expressing the equation of a line is y = mx + b where;

Given the equation

2y = 3x + 4

Rewrite in standard format

y = 3/2 x + 4/2

y = 3/2 x + 2

Get the gradient

mx = 3/2 x

m = 3/2

Hence the gradient of the line is 3/2

b) The line crossed the y-axis when x = 0. Substitute x = 0 into the expression to get the required coordinate

y = 3/2 x + 2

y  = 3/2(0) + 2

y = 2

Hence the co-ordinates of the point where the line crosses the y-axis is at (0, 2)

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a. 3/2.

b. (0, 2).

Step-by-step explanation:

a. 2y = 3x + 4       Divide through by 2:

y = 3/2 x + 2

Comparing this to the general form y = mx + c where m = the gradient  we see  that the gradient = 3/2.

b.  When the line crosses the y-axis x = 0 so we have the equation:

2y = 3(0) + 4

2y = 4

y = 2.

So the  required point is (0, 2).

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6