How do you do this question?

Step-by-step explanation:

The integral is the area under the curve.  When the curve is above the x-axis, the area is positive.  When the curve is below the x-axis, the area is negative.  The integral equals 0, so we want to find the value of b such that the area of the quarter circle is canceled out by the area of the triangle.

Area of the quarter circle is:

A = π/4 r²

A = 9/4 π

Area of the triangle is:

A = ½ bh

9/4 π = ½ (b − 3) (b − 3)

9/2 π = (b − 3)²

b − 3 = 3√(π/2)

b = 3 + 3√(π/2)

b = 6.760

d≈7.07in

step-by-step explanation:

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints