I need help with these two problems. [9 and 10] FORMULAS GIVEN!!

Can someone please solve one of them or both? (I'm sure when one of them is solved, I can do the other)

It would also be nice if you could walk me through it or write what you did step-by-step to solve it! (OPTIONAL)

Formulas if you need them:

RECTANGLE: A = bh
PARALLELOGRAM: A = bh
TRIANGLE: A = 1/2 bh
TRAPEZOID: A = 1/2 h (b1 + b2)
KITE: A = 1/2 d1 x d2
RHOMBUS: A = 1/2 d1 x d2

[I missed the day of school when we went over this section. The teacher told me I should already know how to do it when I ask how to solve. Sorry, please help!]

1. Use Pythagorean Theorem (a²+b²=c²) to solve for missing side of triangle and rectangle. x²+16²=20², or x²+256=400. So, x²=144, and x=12

2. Use formula: 1/2(h)(b1+b2). 1/2 (12) (30+14).

3. Simplify: 1/2 (12) (44)=1/2(528)=264

Area of whole figure is 264 square mm.

Literally same thing but with trigonometry.

1. Use sine to find out length of dotted line: sin(60°)=x/12

2: Simplify: 12*sin(60°)=x. x≈10.4 (rounded to the nearest tenth)

3. Use Pythagorean Theorem to find out last leg of triangle: 10.4²+x²=12²

4: Simplify: 108.16 +x²=144. x²=35.84 ≈ 6

5: Use formula: 1/2(h)(b1+b2). 1/2 (10.4) (30+36)

6: Simplify: 1/2 (10.4) (66) =343.2

7: Area of figure is about 343.2

Remember, this is an approximate answer with rounding, so it might not be what your teacher wants. The best thing to do is do it yourself again.

here's a poem i finished a while ago. i hope you like it and that it inspires you.