A bag holds 11 beads. 7 are red, the rest are white. Two beads are taken at random from the bag. What is the probability that one bead of each colour is taken? You must show your working.
Got 2/4 marks for 14/55

28/55

Step-by-step explanation:

The probability of taking a red bead first and a white bead second is:

P(red, white) = (7/11) (4/10)

P(red, white) = 14/55

The probability of taking a white bead first and a red bead second is:

P(white, red) = (4/11) (7/10)

P(white, red) = 14/55

So the probability that one bead of each color is taken is:

P = P(red, white) or P(white, red)

P = 14/55 + 14/55

P = 28/55

56/110=14/55

Step-by-step explanation:

you get 4 marks!

put me as brainiest please!

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap