One positive number is three larger than another positive number. If sixteen times the reciprocal of the smaller number is added to nine times the reciprocal of the larger number, the sum is one. Find the two number.

= and y = \frac{25+\sqrt{949} }{6} - 3.

Step-by-step explanation:

Take x as the larger number and y as the smaller number.

x + 3 = y

+ = 1

Substitute x + 3 for y in the second equation.

+ = 1

Make a common denominator.

Simplify and get rid of that fraction.

By quadratic formula (and because they must be positive), x = and then y = \frac{25+\sqrt{949} }{6} - 3.

step-by-step explanation:

try remembering the steps

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