Siven that f(x)=x2 - 7 and g(x)= 4 - x, find (f - g)(1), if it exists.

- 9

Step-by-step explanation:

Note that (f - g)(x) = f(x) - g(x)

f(x) - g(x)

= x² - 7 - (4 - x)

= x² - 7 - 4 + x

= x² + x - 11

Thus

(f - g)(1) ← substitute x = 1 into (f - g)(x)

= 1² + 1 - 11

= 1 + 1 - 11

= - 9

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐