The Rogers family and the Ross family each used their sprinklers last summer The Rogers family's sprinkler was used for hoursThe Ross family's Sprinkler was used for 15 hours. There was a combined total output of 1100 L water. What was the water output rate for each sprinkfer if the sum of the two rates was 60 L per hour ?

Question:

The Rogers family and the Ross family each used their sprinklers last summer The Rogers family's sprinkler was used for 30 hours. The Ross family's Sprinkler was used for 15 hours. There was a combined total output of 1100 L water. What was the water output rate for each sprinkfer if the sum of the two rates was 60 L per hour ?

x = 46.66667 L/hr,  y = 13.33333 L/hr

Step-by-step explanation:

Let sprinker's rate for Rogers be x and let rate for Ross be y

Sum of rates = x + y = 60eqn 1

Total output by both families = 15x + 30y = 1100eqn2

Solving simultaneously,

from equation 1, x = 60-y

substituting into eqn 2

15(60-y) + 30y = 1100

900 - 15y + 30y = 1100

collecting like terms

15y = 200

y = 13.33333 L/hr

x = 60 - 13.33333 = 46.66667 L/hr

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.