On a tray there are 13 sugar cookies, 16 chocolate chip cookies, 12 oatmeal raisin cookies, and 14 peanut butter cookies. If Shaina picks one cookie at random, what is the probability that it is not a sugar cookie?

16+12+14.= 42

13+16+12+14. 55

There is a 42/55 or 76.36% chance that Shaina will not pick a sugar cookie

Step-by-step explanation:

13 sugar, 16 chocolate chip, 12 oatmeal, and 14 peanut butter

Total amount besides sugar cookies = 16 + 12 + 14 = 42

42 besides sugar / 55 total = 42/55

There is a 42/55 chance that Shaina will not pic a sugar cookie

42/55 = x/100

Cross Multiply

4200 = 55x

x = 76.36

76.36%

There is a 42/55 or 76.36% chance that Shaina will not pick a sugar cookie from the tray

Hope this helps :)

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right