What is the slope of the line?

The line goes through points (0;1) and (-1/2;0). So:

y = a*x + b

0 = a*(-1/2) + b

-b = -1/2 * a

b = 1/2 * a

y = a * x - a

1 = a * 0 + 1/2 * a

1 = 0 + 1/2 * a

1 = 1/2 * a

2/1 * 1 = a

2 = a

b = 1/2 * a

b = 1/2 * 2

b = 1

So the line is:

y = 2x + 1

Meaning the slope is 2

answer:

the slope is 1/2 hddydvcbeyebebydbd

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

i need more details sorry

step-by-step explanation: