How do you find x and y

(-5,38)

Step-by-step explanation:

Equate the two functions

x^2 - 2x + 3 = -2x + 28

Rearrange and make one side zero.

x^2 - 2x + 2x + 3 - 28 = 0

x^2 - 25 = 0

(x-5)(x+5) = 0

x = 5, -5

We already have the coordinates with x = 5

Using x = -5 in any function, find y

y = -2x + 28

y = -2(-5) + 28 = 10 + 28 = 38

(-5,38)

something over 10 so ? /10

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct