A 40% dye solution is to mixed with a 53% dye solution to get 260L of a 50% solution. How many liters of the 40% and 50% solutions will be needed

From given,

Final solution is 260 liter

Let x be the liters of 40 % dye solution

Then, (260 - x) is the liters of 53 % dye solution

Therefore, according to question,

x liters of 40 % dye solution is mixed with (260 - x) liters of 53 % dye solution to get 260 liters of 50 % dye solution

40 % of x + 53 % of (260 - x) = 50 % of 260

Solve for "x"

Thus 60 liters of 40 % dye solution is used

Then, (260 - x) = 260 - 60 = 200

Thus 200 liters of 53 % dye solution is used

answer:  

123455421

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