A jet airplane departing on time, flying between two airports at an average speed of 540 mph
arrives eight minutes late. Departing on time and flying at an average speed of 480 mph it
arrives fifty-three minutes late. What is the number of miles between the two airports?

The number of miles between the two airports is 11,664,000

Step-by-step explanation:

Distance (d) = Average speed (A) × time (t)

Let the actual time the airport would have arrived be y

When A = 540 mph = 540×60 = 32,400 mpm, t = (y+8) min

d = 32,400(y+8) (1)

When A = 480 mph = 480×60 = 28,800 mpm, t = (y+53) min

d = 28,800(y+53) (2)

Equating both equations

32,400(y+8) = 28,800(y+53)

32,400y+259,200 = 28,800y+1,526,400

32,400y - 28,800y = 1,526,400 - 259,200

3,600y = 1,267,200

y = 1,267,200/3600 = 352 min

d = 32,400(y+8) = 32,400(352+8) = 32,400×360 = 11,664,000 miles

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1