A projectile is launched from ground level with an initial velocity of v 0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by s equals negative 16 t squared plus v 0 t. Find the time(s) that the projectile will (a) reach a height of 288 ft and (b) return to the ground when v 0equals144 feet per second. (a) Find the time(s) that the projectile will reach a height of 288 ft when v 0equals144 feet per second. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.

After 3 seconds while going up and 6 seconds while coming down

Step-by-step explanation:

Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0

Height is given by

where v0 = initial velocity = 144

a) When h =288 ft.

At t= 3 or 6 seconds the projectile would be at height 288 ft.

So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

step-by-step explanation: