Lance says that you can compare any decimal numbers the way that you alphatbetize words you can tell which number is first by comparing each digit from left to right. Is lance thinking correct.

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

Step-by-step explanation:

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.