Can someone help me to solve this question sec(x)sin(x)-2sin(x)=0 [0,2pi) ? ASAP

x = 0, π/3, π, 5π/3

Step-by-step explanation:

sec(x)sin(x) - 2sin(x) = 0

factor out sin(x)

sin(x)[sec(x) - 2] = 0

then solve by splitting into two parts:

sin(x) = 0 and sec(x) - 2 = 0

x = 0, π    and x = π/3, 5π/3 then plug in to original equation to check

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24