Suppose line k has equation x = 3. Compare the areas of ABCD and
A′′B′′C′′D′′=(T⟨1,2⟩∘Rk)(ABCD).
Justify your answer.

In this question we are given a composition of rigid motions. Thus whatever the area moves toward or across, is it is a rigid motion the area and angles will be preserved thus, the area of is equal to the area of A''B''C''D''.

Step-by-step explanation:

As we are given some rigid motions, first we reflect across , which is said to be a rigid motion so, the length and angles of

Thus,

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)