Take the following list of functions and arrange them in ascending order of growth rate. That is, if function g(n) immediately follows function f(n) in your list, then it should be the case that f(n) is O(g(n)). g1(n) = 2√log n g2(n) = 2n g4(n) = n4/3 g3(n) = n(log n)3 g5(n) = n logn g6(n) = 2^(2^n ) g7(n) = 2^(n^2 )

Step-by-step explanation:

From order of growth rate ; Constant < Logarithmic < Polynomial < Exponential

Hence in ascending order ; n (log n)³ < n^4/3 < n^log n < 2√^(logn) < 2n < 2n² < 2^2n

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0