An airplane climbs at an angle of 12 degree with the ground. Find the horizontal distance it has traveled once it has reached an altitude of 500 feet.

The plane has covered 2352.32 feet of horizontal distance.

Given information:

An airplane climbs at an angle of 12 degrees with the ground.

The altitude reached by plane is 500 feet.

A right angles triangle will be formed by the initial position, final position, and the ground. See the attached image.

It is required to find the horizontal distance covered by the plane.

So, the value of horizontal distance covered by the plane will be calculated as,

Therefore, the plane has covered 2352.32 feet of horizontal distance.

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the horizontal distance travelled is 2352 feet

Step-by-step explanation:

The altitude of the airplane, the horizontal distance that it travelled and the angle, θ formed with the ground combine to form a right angle triangle.

The horizontal distance that it travelled represents the adjacent side of the right angle triangle.

The altitude that it reached represents the opposite side of the right angle triangle. To determine the horizontal distance that it has travelled, h, we would apply the tangent trigonometric ratio which is expressed

Tan θ = opposite side/adjacent side

Therefore,

Tan 12 = 500/h

h = 500/Tan 12 = 500/0.2126

h = 2352 feet

45

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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