A certain brand of trading cards is available in smaller packs that cost $2 each. Assume that any given pack has a 10% chance of containing a rare card, independently of other packs. Alice will buy and open a pack until she gets a rare card, but she will not buy more than five. Let M be the amount of money (in dollars) that Alice will spend. a. Find the distribution of the random variable (and provide it as a chart).b. Calculate the expected value of the random variable. Do not round values.

Step-by-step explanation:

P(m=6) = 0.10 x 0.90^2 = 0.081

P(m=8) = 0.10 x 0.90^3 = 0.0729

P(m=10) = 1- [p(m=2) + p(m=4) + p(m=6) + p(m=8)

= 1 - 0.3439

= 0.6561

b) the expected value of the random variable ; E(M) = Summation(Px)

= 2x0.10 + 4x0.09 + 6x0.081 + 8x0.0729 + 10x0.6561

= 8.1902

The distribution of the random variable =

M    P(M)

2     0.10

4     0.09

6     0.081

8     0.0729

10   0.6561

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen

you would need to also lose 1 point for each of the other outcomes for it to be fair.

step-by-step explanation: