ABCD is a square. M is the midpoint of BC and N is the midpoint of CD. A point is selected at random in the square. Calculate the probability that it will liein the triangle MCN.

1/8 or 0.125

Step-by-step explanation:

Let x be the length of the sides of the square ABCD.

Therefore, the length of CN and CM is x/2.

The area of the triangle MCN is:

The area of the square ABCD is:

Thus, the probability that a random point lies in the triangle MCN is:

The probability that the point will lie in the triangle MCN is 1/8 or 0.125.

(-5,-28)

i graphed to on desmos.

english, cause i can’t you