A motorist encounters four consecutive traffic lights, each equally likely to be red or green. Let be the number of green lights passed by the motorist before being stopped by a red light. What is the probability distribution of E?

P (X = 0) = 0.50          P (X = 3) = 0.0625

P (X = 1) = 0.25           P (X = 4) = 0.0625

P (X = 2) = 0.125

Step-by-step explanation:

The random variable E is denoted as the number of green lights passed by the motorist before being stopped by a red light.

Then the random variable E can take values, E = {0, 1, 2, 3, 4}

The probability distribution table for the random variable E attached below.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier