According to a study, nearly 80% of workers in law libraries are satisfied with their job. Assume the true proportion of law librarians are satisfied with their job is 0.8. In a random sample of 20 law librarians, what is the probability that at most 4 are unsatisfied with their job?

0.618

Step-by-step explanation:

This is a binomial distribution. We are to determine the probability of people unsatisfied. If we denote the probability of being satisfied with , then . Let be the probability of being unsatisfied. Then

Since the random sample is 20 and is small enough, we can use the Poisson probability function

where is the mean and is given by .

Denoting the probability of at most 4 unsatisfied with ,

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.

a. (14,375+570)(5.3) b. 158,417$

step-by-step explanation:

a. you are basically just setting up the equation. f= amount of debt hence 14,375. g= how much she is borrowing from her parents weekly hence 570 and t= the interest on her debt. creating the equation.

b.   14,375+570= 14,945

      14,945 x 5.3 = 79,208.5

      79,208.5 x 2(years) = 158,417(answer)