Suppose that the probability of getting a job offer (from a specific company) is 0.16. Suppose that we observe empirically that given that an applicant for the job was in fact offered a job, the probability of an on campus interview was 0.93. Also, we observe empirically that given the group that were not offered a job the probability of an on campus interview was of 0.08. Given that a person got a campus interview, what is the probability that they get a job offer? (Answer to five decimal places).

0.68889

Step-by-step explanation:

This can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

Given that a person got a campus interview, what is the probability that they get a job offer?

P(B) is the probability of getting a job offer. So

P(A/B) is the probability of getting a campus interview, given that they get a job offer. So P(A/B) = 0.93.

P(A) is the probability ofgetting a campus interview. Of those 16% who got a job, 93% had a campus interview. Of those 84% who did not get a job, 8% had a campus interview. So

Finally

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl