The following data represent the flight time (in minutes) of a random sample of seven flights from one city to another city. 282, 268, 258, 264, 255, 261, 267 Compute the range and sample standard deviation of flight time. The range of flight time is nothing minutes.

range = 27 and standard deviation= 8.83

Step-by-step explanation:

Range = highest - lowest

Range = 282 - 255

Range= 27

Let m be mean

M=mean=sum/n

Mean= (282+268+258+264+255+261+267) / 7

M=1855/7

M=265

The standard deviation sample formula:

S.D = sqrt( Summation of |x-m|^2 / n-1)

Let start finding:

|x-m|^2

For 1st: |282-265|^2=289

For 2nd: |268-265|^2=9

For 3rd: |258-265|^2=49

For 4th: |264-265|^2=1

For 5th: |255-265|^2=100

For 6th: |261-265|^2=16

For 7th: |267-265|^2=4

Summation of |x-m|^2 = 468

The standard deviation formula is :

S.D = sqrt( Summation of |x-m|^2 / n-1)

S.D= sqrt(468 / 6)

S.D=sqrt(78)

S.D= 8.83

answer: 12

step-by-step explanation:

because yes

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula