1.
An object 2.0-cm tall is located 10.0-cm in front of a converging lens
with a focal length of 5.0-cm. Find the location and height of the
image. Locate lens toward the center of your paper.

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

=3

Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

v = -12 cm

m = 12/20 = 0.6

size of final image = .6 x 30 = 18 cm

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

5 quiero

6 vamos

7 puedan

8 quiero

9pedemos

10 dorme

step-by-step explanation: