The width of a rectangle is 28 cm. the perimeter of the rectangle is no more than 125cm. what is the largest possible length of the rectangle

34.5 cm

Step-by-step explanation:

Perimeter of rectangle = Length + Length + Width + Width

= 2Length + 2 Width

given width = 28 cm, equation becomes

Perimeter = 2Length + 2(28)

Perimeter = (2L + 56)  (eq1)

we are also given that the perimeter is no more than 125cm

this means that the perimeter is less than or equal to 125 cm i.e,

perimeter ≤ 125 cm

combining this with (eq 1) above,

(2L + 56) ≤ 125

2L + 56 ≤ 125  (subtract 56 from both sides)

2L ≤ 125 - 56

2L ≤ 69  (divide both sides by 2)

L ≤ 69 / 2

L≤ 34.5

hence the largest possibel length is 34.5 cm

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

fd

step-by-step explanation: