What is the equation of the following graph.

y = cos x + 2

Step-by-step explanation:

1. By looking at the shape of the graph, you can infer that it is either a cos or sin graph.

2. Look at the y value when X = 0. It starts with an inverted bell shape curve, from there we can infer that it is a cosine graph. if it is a sin graph, the shape will be like a toppled S shape curve.

3. This part is a bit trial and error for me:

Let X = 0,

cos 0 = 1

But the graph shows that when X = 0, Y = 3,

So there are 2 possibilities:

However when X = π,

So cos x + 2 is the only option.

Hope it makes sense to you. Sorry if it sounds confusing, English is not my first language.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

answer: 10 meter

step-by-step explanation:

need details