A standing wave pattern is observed in a thin wire with a length of3.00m. The equation of the wave is
y=(0.002m)sin(πx)cos(100πt)
where x is in meters and t is in seconds.

a. How many loops does this pattern exhibit?
b. What is the fundamental frequency of vibration of the wire?
c. If the original frequency is held constant and the tension inthe wire is increased by a factor of nine, how many loops arepresent in the new pattern?

a) How many loops does this pattern exhibit = 3Loops

b) What is the fundamental frequency of vibration of the wire = 50Hz

c) how many loops arepresent in the new pattern = 1 Loop

Step-by-step explanation:

The concept of general wave equation is applied and then compared to the equation given in the question to determine the amplitude A, and angular frequency w as shown in the attached file.

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

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