At the beginning of a Major League Baseball season, a panel of sports writers decided that the Los Angeles Dodgers were the most likely team to win the World Series that year. This is an example of using probability.
a. Classical b. Empirical c. Subjective

c. Subjective

Step-by-step explanation:

In classical probability, all of the possible outcomes are equally likely, which means that all teams would have the same chance of winning.

In empirical probability, trials and experiments are used to estimate probability based on the outcome of the trials. In this case, teams would have to play each other multiple times to determine each team's probability if winning.

In subjective probability,  an individual's personal judgment or experience on a topic is used to predict the likelihood of an outcome.

Since the sports writers are using their baseball knowledge to make a prediction, this is an example of subjective probability.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

step-by-step explanation: