Some IQ tests are standardized to a Normal model N(100,18). a) What cutoff value bounds the highest 15% of all IQs? b) What cutoff value bounds the lowest 35% of the IQs? c) What cutoff values bound the middle 80% of the IQs?

A) 119

B) 93

C) 77 and 123

Step-by-step explanation:

Mean m = 100

Standard deviation d = 18

A) IQ value for the highest 15% of the IQ;

P(z<x) = 1 - 0.15 = 0.85

Since P(z<x) = ¢(Z) = 0.85

Z = 1.04

Recall that,

Z = (x-m)/d

x = dZ + m = 1.04*18 + 100

x = 118.72 approximately

x = 119

Therefore, the cutoff value bounds the highest 15% of all IQs is 119

B) For the lowest 35% of the IQs

P(z<x) = 0.35

Since P(z<x) = ¢(Z) = 0.35

Z = - 0.39

Recall that,

Z = (x-m)/d

x = dZ + m = -0.39*18 + 100

x = 92.98 = 93

Therefore, the cutoff value bounds the lowest 35% of the IQs is 93

C) cutoff values bound the middle 80% of the IQs

P(x<z<y) = 0.8 = 0.9 - 0.1

Since P(z<x) = ¢(Z)

P(x<z<y) = 0.9 - 0.1 = ¢(Z1) - ¢(Z2)

Z1 = 1.28

Z2 = -1.28

Recall that,

Z1 = (x-m)/d

x = dZ1 + m = 1.28*18 + 100

x = 123

Z2 = (y-m)/d

y = dZ2 + m = -1.28*18 + 100

y = 77

Therefore, cutoff values bound the middle 80% of the IQs are 77 and 123

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2