. (From Homework #5) On average there are 22 imperfections in 100 meters of optical cable. The imperfections can be modeled using the Poisson distribution. a) What is the expected length of cable between imperfections? b) The application from homework #5 required a 25-meter length of cable. What is the probability that the length until the next imperfection will be more than 25 meters?

10 * 563.67 = 5636.7

answer: plz put a pic in so i can answer it

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

do you have a picture of the table