What is the equation of the line that passes through (1, 3) and (-2, -3)?

y = -2 x + 1

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

To find the slope(m), use the slope formula:

     And plug in the two points

(-2, -3) = (x₁, y₁)

(1, 3) = (x₂, y₂)        

[lines go from left to right, so the point furthest to the left is the 1st point]

  [two negative signs cancel each other out and become positive]

m = 2      Now that you know the slope, plug it into the equation

y = mx + b

y = 2x + b      To find b, plug in either of the points into the equation, it doesn't matter which, I will use (1, 3)

3 = 2(1) + b      Subtract 2 on both sides to get "b" by itself

3 - 2 = 2 - 2 + b

1 = b

y = 2x + 1

step-by-step explanation:

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other answer is correct. i had used the radius of the radius somehow. a website: