For t > 30, L(t), the linear approximation to A at t = 30, is a better model for the amount of grass clippings remaining in the bin. Use L(t) to predict the time at which there will be 0.5 pound of grass clippings remaining in the bin. Show the work that leads to your answer.

35 days

Step-by-step explanation:

We know that L(t) is the tangent to the line A(t) at t = 30

At t = 30:

A (30) ≈ 0.783 →(30, 0.783) = (t, A(t))

A¹ (30) ≈ -0.56

let -0.56 = M

For a linear function, a straight line equation applies which leads to

(y-y₁) = m (x-x₁)                                                   ...1

So for this problem we have;

A (t)-0.783 = -0.56 (t - 30)

when there is 0.5 pounds of grass, A (t) - 0.5, then using the equation (1)

(0.5 - 0.783) = -0.56 (t-30)

                   t = 35.054

                     ≈ 35 days

853.3

step-by-step explanation:

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.