A philanthropic organization knows that its donors have an average age near 60 and is considering taking out an ad in the Canadian Association of Retired People (CARP) magazine. An analyst wonders what proportion of their donors are actually 50 years old or older. He takes a random sample of the records of 467 donors and found that 300 were actually 50 years old or older. Construct a 95% confidence interval for the proportion of donors who are 50 years old or older.

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

exactly you go it

step-by-step explanation:

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.