Graph f(x) = 3(2):
L-LJUJ_ALL_
LI
--44-4
4-

a=-
זירז־ז־ו־רז־ד־ר
ו ו ו ו ו ו ו ד
ו ו ו ו ו ו ו ו
+-+ -+-+- +-+-ד
ו ו ו ו ו ו ו
-- --ז-ו-רז־ד־ר
־ז
ה ו
ו ו
-ז
ו ן
־ז
b=
--4-
--4-
-4-
--
y-intercept=
ו ו ו ו ו ו ו
-
-
+
-
+
-
FA
FR
-
+
-
+
-ז
ו ו ן ן ן ן ן ן ן
רוח־ז־ן־רז־ד־ר־ז
-ב-- -
1
-
1
1
-
1 -ב L
-
L
ו ו ו ו ו ו ו ו ו
ו ו ו ו ו ו ו ו
end behavior:
4-
-E
+
+-
+-
+
+ -
--
-
--
1-14-1-1-LI-
ו
ו
ו
ו
ו
ב
ו
ו
ו
L
Growth or Decay?
-
-

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!