You are rushing out to get to your appointment in 30 minutes. From experience you know that most of the time you travel this distance in 30 minutes. However, half of the time there is heavy traffic. In the past, there has been heavy traffic and you have made it to your appointment within 30 minutes 34% of the time. You get out on the street and see that there is heavy traffic. What is the chance you will get to your appointment on time?

Probability P(getting there on time) = 0.68

Step-by-step explanation:

Let H be heavy traffic

Let T be getting there on time

Half of the time is heavy traffic that is:

Probability P (H)= 0.5

Normally you get there 30 minutes 34% of the times

The mean Probability p(H and T)=0.34

Probability P (getting there on time)= p(H and T) /P(H) = 0.34/0.5 = 0.68

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option