In Exercises 1 and 2, find the equilibrium solutions of the differential equation specified.1) dy/dt = (y + 3)/(1 - y)2) dy/dt = (t² - 1)(y² - 2)/(y ² - 4)

1. Equilibrium solution: y= -3

2. Equilibrium solution y= ±1.414

Step-by-step explanation:

Thinking process:

The equilibrium solution can only be derived when

1. Let's look at the first equation:

equating to the expression gives

y + 3 = 0

     y = -3

Therefore, the equilibrium solution occurs at y = -3

2. Let's look at the second solution:

dividing each side by (t²-1) gives

1/(t²-1) = (y²-2)/ (y²-4)

factorizing the right hand side gives:

at equilibrium:  , then

y² - 2 = 0

solving for y gives y = ±√2

                                 = ±1.414

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: