In bridge, the 52 cards of a standard deck are dealt to four players. How many different ways are there to deal bridge hands to four players?

The number of different ways to deal bridge hands to four players = 53644737765488792839237440000

Step-by-step explanation:

Total number of cards, N = 52

Each of the four players will receive (52/4) = 13 cards.

Each player 1, 2, 3 and 4 will receive

n₁ = 13, n₂ = 13, n₃ = 13, n₄ = 13

Distributing N different & unique objects into k distinguishable boxes such that nᵢ objects are place in box i (where i= 1,2, 3, 4k) can be done in

(n!)/(n₁!n₂!n₃!n₄!nₖ!)

So, for this problem, the number of different ways to deal bridge hands to four players = (52!)/(13!13!13!13!) = (52!)/(13!)4

= 53644737765488792839237440000

Hope this Helps!!!

pi x^2

step-by-step explanation:

pi times x squared