Asap for brainliest: the time required to finish a test in normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. what is the z-score for a student who finishes the test in 23 minutes? show work : )

The z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of time to finish a test = 60 minutes

Standard deviation of time to finish a test = 10 minutes

Time that a student finishes the test = 23 minutes

2. What is the z-score for the student?

z-score = (Time that a student finishes the test - Mean of time to finish a test)/Standard deviation of time to finish a test

Replacing with the real values:

z-score = (23 -60)/10 = -37/10 = -3.7

z-score = -3.7 and p (-3.7) = 0.00011 or 0.011%

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explanation:

i would say c is the best answer, hope it's right!

good luck! =)

cutie~