Adult tickets to a basketball game cost $5. student tickets cost $1. a total of $2,703 was collected on the sale of 1,167 tickets. how many of each type of ticket were sold?

no. of students ticket=783

no. of adult ticket=384

Step-by-step explanation:

assumption: we find the number of students ticket

1167×5=5835

5835-2703=3132

5-1=4

3132÷4=783(number of students ticket)

1167-783=384(number of adult tickets)

$655.61 which is option c

step-by-step explanation:

price of house =   $146,000

initial rate = 3.5%

mortgaged paid in this = 3.5 % of $146,000

                                        =

                                        =$5110

the total years would be = 7

total mortgaged paid = 7 * $5110

                                      =$35770

remaining money = $146000-35770

                                =$110230

new mortgaged payment = 5 % of 110230

                                            =  

                                            =$655.61