If a chain of 30 identical short springs linked end-to-end has a stiffness of 450 n/m, what is the stiffness of one short spring?

The stiffness of one short spring is 13500 N/m

Solution:

We are given a chain with number of spring N = 30 and linked end to end ( in series) and stiffness of this chain is 450 N/m

We have to find the stiffness of one short spring

The springs are identical, which means they have same stiffness

The stiffness of one spring in series is given as:

Where,

N is the number of springs

is the stiffness of one spring

is the stiffness of this chain

Substituting,

Therefore,

Thus the stiffness of one short spring is 13500 N/m

darn right!

step-by-step explanation:

steve kerr's sons name is let that skin in.

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: