Mathematics

Mathematics, 23.09.2019 16:40, isabelvaldez123

How do you get the midpoint of a line segment?
using shortcuts

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Mathematics, 24.07.2019 00:50, dbryrob9148

Given: δabc prove: the three medians of δabc intersect at a common point. when written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point: statements justifications point f is a midpoint of line segment ab point e is a midpoint of line segment ac draw line segment be draw line segment fc by construction point g is the point of intersection between line segment be and line segment fc intersecting lines postulate draw line segment ag by construction point d is the point of intersection between line segment ag and line segment bc intersecting lines postulate point h lies on line segment ag such that line segment ag ≅ line segment gh by construction i line segment bd ≅ line segment dc properties of a parallelogram (diagonals bisect each other) ii line segment fg is parallel to line segment bh and line segment ge is parallel to line segment hc midsegment theorem iii line segment gc is parallel to line segment bh and line segment bg is parallel to line segment hc substitution iv bgch is a parallelogram properties of a parallelogram (opposite sides are parallel) line segment ad is a median definition of a median which is the most logical order of statements and justifications i, ii, iii, and iv to complete the proof? ii, iii, i, iv iii, ii, i, iv ii, iii, iv, i iii, ii, iv, i

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Mathematics, 30.08.2019 23:00, mccdav5100

Line segment fg is the midpoint of isosceles triangle abc and line segment km is the midpoint of trapezoid cdef. line segment ef is parallel to line segment km is parallel to line segment dc. find the following measures. show your work and describe any properties or theorems you use.

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Mathematics, 31.08.2019 00:20, hmu323

(i need the answer right now ) δa'b'c' was constructed using δabc and line segment eh. 2 triangles are shown. line e h is the line of reflection. line segment b b prime has a midpoint at point d. line segment a a prime has a midpoint at point f. line segment c c prime has a midpoint at point g. for to be the line of reflection between and , which statements must be true? select three options. bd = db' df = fg m∠efa = 90° the line of reflection, eh, is the perpendicular bisector of bb', aa', and cc'. δabc is not congruent to δa'b'c'.

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Mathematics, 17.10.2019 23:30, Kylehc21

Given: b is the midpoint of segment a c. segment b c is congruent to segment d e. prove: segment a b is congruent to segment d e. art: three line segments a b, b c, and d e. line segments a b and b c make a straight line. line segment d e intersects line segment b c. point d lies on upward-left direction from line segment b c. statements reasons 1. b is the midpoint of ac.given 2. ab≅bc definition of midpoint 3. bc≅de given 4. ab≅de what is the reason for statement 4 of the two-column proof? symmetric property of equality segment congruence postulate segment addition postulate transitive property of congruence

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How do you get the midpoint of a line segment?
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