Mathematics, 29.01.2020 20:58, spencertodd742
Differentiate. (assume k is a . y = 1 / (p + ke^p). i tried using the quotient (f/g)' = (gf' - fg') / g^2. and ended up with . (1-pke^(p-1)) / (p+ke^p)^2. which is apparently wrong.
Answers: 1
![\displaystyle\frac{d}{dp}\bigg[ \displaystyle\frac{1}{p + ke^p}\bigg] =-\displaystyle\frac{ ke^p + 1}{(p + ke^p)^2}](/tpl/images/0483/2958/897b5.png)
![\displaystyle\frac{d}{dp}\bigg[ \displaystyle\frac{1}{p + ke^p}\bigg]\\\\= \displaystyle\frac{(p+ke^p)(1)' - (1)(p + ke^p)'}{(p + ke^p)^2}\\\\= \displaystyle\frac{(p+ke^p)(0) - (1)(1 + ke^p)}{(p + ke^p)^2}\\\\= \displaystyle\frac{-(1 + ke^p)}{(p + ke^p)^2}\\\\=-\displaystyle\frac{ ke^p + 1}{(p + ke^p)^2}](/tpl/images/0483/2958/cd1ef.png)
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