Mathematics, 25.10.2019 10:43, babyjulie61

What is the equation, in standard form, of a parabola that contains the following points? (–2, –20), (0, –4), (4, –20)

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From the following points, we can see that for y equals -20, there are two x's. Hence the equation should contain x^2. The graph is going downward too so we are expecting a -4a. The equation is (y-k) = 4a (x-h)^2. h as the x component of the vertex is 1 from the points. substituting, we get (y-k) = 4a (x-1)^2. we substitute the points to get k and a, k is equal to -2 and a is equal to -0.5. Hence the equation becomes (y+2) = -2 (x-1)^2. The standard form is -2x^2 + 4 x - 4 - y = 0.

answered: willveloz4

The standard form of the parabola is $\boxed{y =- 2{x^2} + 4x - 4}.$

Further explanation:

The standard form of the parabola can be expressed as follows,

$\boxed{y = a{x^2} + bx + c}$

Here, a represents the coefficient of ${x^2},b$ is the coefficient of and is the constant term.

The vertex form of the quadratic equation can be expressed as follows,

$\boxed{y = a{{\left( {x - h} \right)}^2} + k}.$

Here, $\boxed{\left( {h,k} \right)}$ is the vertex point, h is the coordinate of the equation and k is the y-coordinate.

Given:

The points are $A\left( { - 2, - 20} \right), B\left( { 0, - 4} \right)$ and $C\left( { 4, - 20} \right).$

Explanation:

Substitute for and for in equation $y = a{x^2} + bx + c.$

$\begin{aligned}- 20&= a{\left({ - 2} \right)^2} + b\left({ - 2} \right) + c\\- 20&= 4a - 2b + c\\- 20 - c&= 4a - 2b\\\end{aligned}$

Substitute for and for in equation $y = a{x^2} + bx + c.$

$\begin{aligned}- 4&= a{\left( 0 \right)^2} + b\left( 0 \right)+ c\\- 4&= 0 + 0 + c\\- 4&= c\\\end{aligned}$

Substitute for and for in equation $y = a{x^2} + bx + c.$

$\begin{aligned}- 20&= a{\left(4\right)^2} + b\left( 4\right) + c \hfill\\- 20&= 16a + 4b + c \hfill\\- 20 - c&= 16a + 4b \hfill\\\end{aligned}$

Substitute for in equation - 20 - c = 4a - 2b.

$\begin{aligned}- 20 - c&= 4a - 2b\\- 20 + 4 &= 4a - 2b\\- 16&= 4a - 2b\\- 8&= 2a - b\\\end{aligned}$

Substitute for in equation - 20 - c = 16a + 4b.

$\begin{aligned}- 20 - c&= 16a + 4b\\- 20 + 4&= 16a + 4b\\- 16 &= 16a + 4b\\ - 4&= 4a + b\\\end{aligned}$

Add the equations - 4 = 4a + b and - 8 = 2a - b.

$\begin{aligned}- 8 - 4 &= 2a - b + 4a + b\\ - 12&= 6a\\\frac{{ - 12}}{6}&= a\\- 2&= a\\\end{aligned}$

The value of b can be obtained as follows,

$\begin{aligned}4\left({ - 2}\right) + b& =- 4\\- 8 + b&=- 4\\b&= - 4 + 8\\\end{aligned}$

The standard form of the parabola is $\boxed{y= - 2{x^2} + 4x - 4}.$

Learn more:

1. Learn more about inverse of the function .

2. Learn more about equation of circle .

3. Learn more about range and domain of the function

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Quadratic equation

Keywords: quadratic equation, standard form, parabola, contain points, (-2,-20), (0,-4), (4,-20), vertex form of the equation, biased, equation, formula, parabola, general equation, explained better.

answered: Guest

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

answered: Guest

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step-by-step explanation:

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